2(x-2)-4=8(x-3)+15

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Solution for 2(x-2)-4=8(x-3)+15 equation: 



2(x-2)-4=8(x-3)+15

We move all terms to the left:

2(x-2)-4-(8(x-3)+15)=0

We multiply parentheses

2x-(8(x-3)+15)-4-4=0



We calculate terms in parentheses: -(8(x-3)+15), so:

8(x-3)+15

We multiply parentheses

8x-24+15

We add all the numbers together, and all the variables

8x-9

Back to the equation:

-(8x-9)



We add all the numbers together, and all the variables

2x-(8x-9)-8=0

We get rid of parentheses

2x-8x+9-8=0

We add all the numbers together, and all the variables

-6x+1=0

We move all terms containing x to the left, all other terms to the right

-6x=-1

x=-1/-6

x=1/6

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