2(x-2)-4x=3x(x+1)-9x

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Solution for 2(x-2)-4x=3x(x+1)-9x equation: 



2(x-2)-4x=3x(x+1)-9x

We move all terms to the left:

2(x-2)-4x-(3x(x+1)-9x)=0

We add all the numbers together, and all the variables

-4x+2(x-2)-(3x(x+1)-9x)=0

We multiply parentheses

-4x+2x-(3x(x+1)-9x)-4=0



We calculate terms in parentheses: -(3x(x+1)-9x), so:

3x(x+1)-9x

We add all the numbers together, and all the variables

-9x+3x(x+1)

We multiply parentheses

3x^2-9x+3x

We add all the numbers together, and all the variables

3x^2-6x

Back to the equation:

-(3x^2-6x)



We add all the numbers together, and all the variables

-2x-(3x^2-6x)-4=0

We get rid of parentheses

-3x^2-2x+6x-4=0

We add all the numbers together, and all the variables

-3x^2+4x-4=0

a = -3; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-3)·(-4)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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