2(x-2)-5(x-5)=(x-8)-2(x-2)

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Solution for 2(x-2)-5(x-5)=(x-8)-2(x-2) equation: 



2(x-2)-5(x-5)=(x-8)-2(x-2)

We move all terms to the left:

2(x-2)-5(x-5)-((x-8)-2(x-2))=0

We multiply parentheses

2x-5x-((x-8)-2(x-2))-4+25=0



We calculate terms in parentheses: -((x-8)-2(x-2)), so:

(x-8)-2(x-2)

We multiply parentheses

(x-8)-2x+4

We get rid of parentheses

x-2x-8+4

We add all the numbers together, and all the variables

-1x-4

Back to the equation:

-(-1x-4)



We add all the numbers together, and all the variables

-3x-(-1x-4)+21=0

We get rid of parentheses

-3x+1x+4+21=0

We add all the numbers together, and all the variables

-2x+25=0

We move all terms containing x to the left, all other terms to the right

-2x=-25

x=-25/-2

x=12+1/2

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