2(x-2)/3=2(x+5)/10

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Solution for 2(x-2)/3=2(x+5)/10 equation: 



2(x-2)/3=2(x+5)/10

We move all terms to the left:

2(x-2)/3-(2(x+5)/10)=0

We calculate fractions


2x/()+(-(2(x+5)*3)/()=0



We calculate terms in parentheses: +(-(2(x+5)*3)/(), so:

-(2(x+5)*3)/(

We multiply all the terms by the denominator


-(2(x+5)*3)



We calculate terms in parentheses: -(2(x+5)*3), so:

2(x+5)*3

We multiply parentheses

6x+30

Back to the equation:

-(6x+30)



We get rid of parentheses

-6x-30

Back to the equation:

+(-6x-30)



We get rid of parentheses

2x/()-6x-30=0

We multiply all the terms by the denominator


2x-6x*()-30*()=0

We add all the numbers together, and all the variables

2x-6x*()=0

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