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2(x-2)=2(x+3)
We move all terms to the left:
2(x-2)-(2(x+3))=0
We multiply parentheses
2x-(2(x+3))-4=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
2x-2x-6-4=0
We add all the numbers together, and all the variables
-10!=0
There is no solution for this equation
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