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2(x-2)=3(x-2)+1
We move all terms to the left:
2(x-2)-(3(x-2)+1)=0
We multiply parentheses
2x-(3(x-2)+1)-4=0
We calculate terms in parentheses: -(3(x-2)+1), so:We get rid of parentheses
3(x-2)+1
We multiply parentheses
3x-6+1
We add all the numbers together, and all the variables
3x-5
Back to the equation:
-(3x-5)
2x-3x+5-4=0
We add all the numbers together, and all the variables
-1x+1=0
We move all terms containing x to the left, all other terms to the right
-x=-1
x=-1/-1
x=1
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