2(x-2)=3(x-2)+1

Solution for 2(x-2)=3(x-2)+1 equation:

2(x-2)=3(x-2)+1

We move all terms to the left:

2(x-2)-(3(x-2)+1)=0

We multiply parentheses

2x-(3(x-2)+1)-4=0


We calculate terms in parentheses: -(3(x-2)+1), so:

3(x-2)+1

We multiply parentheses

3x-6+1

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)


We get rid of parentheses

2x-3x+5-4=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1