2(x-2)=3(x-8)+10

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Solution for 2(x-2)=3(x-8)+10 equation: 



2(x-2)=3(x-8)+10

We move all terms to the left:

2(x-2)-(3(x-8)+10)=0

We multiply parentheses

2x-(3(x-8)+10)-4=0



We calculate terms in parentheses: -(3(x-8)+10), so:

3(x-8)+10

We multiply parentheses

3x-24+10

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We get rid of parentheses

2x-3x+14-4=0

We add all the numbers together, and all the variables

-1x+10=0

We move all terms containing x to the left, all other terms to the right

-x=-10

x=-10/-1

x=+10

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