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2(x-2)=4(3+2x)
We move all terms to the left:
2(x-2)-(4(3+2x))=0
We add all the numbers together, and all the variables
2(x-2)-(4(2x+3))=0
We multiply parentheses
2x-(4(2x+3))-4=0
We calculate terms in parentheses: -(4(2x+3)), so:We get rid of parentheses
4(2x+3)
We multiply parentheses
8x+12
Back to the equation:
-(8x+12)
2x-8x-12-4=0
We add all the numbers together, and all the variables
-6x-16=0
We move all terms containing x to the left, all other terms to the right
-6x=16
x=16/-6
x=-2+2/3
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