2(x-2)=4+(2x-8)

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Solution for 2(x-2)=4+(2x-8) equation: 



2(x-2)=4+(2x-8)

We move all terms to the left:

2(x-2)-(4+(2x-8))=0

We multiply parentheses

2x-(4+(2x-8))-4=0



We calculate terms in parentheses: -(4+(2x-8)), so:

4+(2x-8)

determiningTheFunctionDomain
(2x-8)+4

We get rid of parentheses

2x-8+4

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

2x-2x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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