2(x-2)=4x+2-2(-5x-5)

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Solution for 2(x-2)=4x+2-2(-5x-5) equation: 



2(x-2)=4x+2-2(-5x-5)

We move all terms to the left:

2(x-2)-(4x+2-2(-5x-5))=0

We multiply parentheses

2x-(4x+2-2(-5x-5))-4=0



We calculate terms in parentheses: -(4x+2-2(-5x-5)), so:

4x+2-2(-5x-5)

determiningTheFunctionDomain
4x-2(-5x-5)+2

We multiply parentheses

4x+10x+10+2

We add all the numbers together, and all the variables

14x+12

Back to the equation:

-(14x+12)



We get rid of parentheses

2x-14x-12-4=0

We add all the numbers together, and all the variables

-12x-16=0

We move all terms containing x to the left, all other terms to the right

-12x=16

x=16/-12

x=-1+1/3

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