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2(x-2)=4x-(2x-4)
We move all terms to the left:
2(x-2)-(4x-(2x-4))=0
We multiply parentheses
2x-(4x-(2x-4))-4=0
We calculate terms in parentheses: -(4x-(2x-4)), so:We get rid of parentheses
4x-(2x-4)
We get rid of parentheses
4x-2x+4
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
2x-2x-4-4=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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