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2(x-22)=10(10-x)
We move all terms to the left:
2(x-22)-(10(10-x))=0
We add all the numbers together, and all the variables
2(x-22)-(10(-1x+10))=0
We multiply parentheses
2x-(10(-1x+10))-44=0
We calculate terms in parentheses: -(10(-1x+10)), so:We get rid of parentheses
10(-1x+10)
We multiply parentheses
-10x+100
Back to the equation:
-(-10x+100)
2x+10x-100-44=0
We add all the numbers together, and all the variables
12x-144=0
We move all terms containing x to the left, all other terms to the right
12x=144
x=144/12
x=12
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