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2(x-3)(1-2x)=3x
We move all terms to the left:
2(x-3)(1-2x)-(3x)=0
We add all the numbers together, and all the variables
2(x-3)(-2x+1)-3x=0
We add all the numbers together, and all the variables
-3x+2(x-3)(-2x+1)=0
We multiply parentheses ..
2(-2x^2+x+6x-3)-3x=0
We multiply parentheses
-4x^2+2x+12x-3x-6=0
We add all the numbers together, and all the variables
-4x^2+11x-6=0
a = -4; b = 11; c = -6;
Δ = b2-4ac
Δ = 112-4·(-4)·(-6)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5}{2*-4}=\frac{-16}{-8} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5}{2*-4}=\frac{-6}{-8} =3/4 $
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