2(x-3)(x-5)=0

Solution for 2(x-3)(x-5)=0 equation:

2(x-3)(x-5)=0

We multiply parentheses ..

2(+x^2-5x-3x+15)=0

We multiply parentheses

2x^2-10x-6x+30=0

We add all the numbers together, and all the variables

2x^2-16x+30=0

a = 2; b = -16; c = +30;
Δ = b2-4ac
Δ = -162-4·2·30
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4}{2*2}=\frac{12}{4}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4}{2*2}=\frac{20}{4}
=5
$