2(x-3)+18=3(x+4)

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Solution for 2(x-3)+18=3(x+4) equation:



2(x-3)+18=3(x+4)
We move all terms to the left:
2(x-3)+18-(3(x+4))=0
We multiply parentheses
2x-(3(x+4))-6+18=0
We calculate terms in parentheses: -(3(x+4)), so:
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
We add all the numbers together, and all the variables
2x-(3x+12)+12=0
We get rid of parentheses
2x-3x-12+12=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0

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