2(x-3)+18=3(x+4)

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Solution for 2(x-3)+18=3(x+4) equation: 



2(x-3)+18=3(x+4)

We move all terms to the left:

2(x-3)+18-(3(x+4))=0

We multiply parentheses

2x-(3(x+4))-6+18=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

2x-(3x+12)+12=0

We get rid of parentheses

2x-3x-12+12=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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