2(x-3)+1=11(x+2)

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Solution for 2(x-3)+1=11(x+2) equation: 



2(x-3)+1=11(x+2)

We move all terms to the left:

2(x-3)+1-(11(x+2))=0

We multiply parentheses

2x-(11(x+2))-6+1=0



We calculate terms in parentheses: -(11(x+2)), so:

11(x+2)

We multiply parentheses

11x+22

Back to the equation:

-(11x+22)



We add all the numbers together, and all the variables

2x-(11x+22)-5=0

We get rid of parentheses

2x-11x-22-5=0

We add all the numbers together, and all the variables

-9x-27=0

We move all terms containing x to the left, all other terms to the right

-9x=27

x=27/-9

x=-3

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