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2(x-3)+1=3(x)-5
We move all terms to the left:
2(x-3)+1-(3(x)-5)=0
We multiply parentheses
2x-(3x-5)-6+1=0
We get rid of parentheses
2x-3x+5-6+1=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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