2(x-3)+1=3x+2-(2-x)

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Solution for 2(x-3)+1=3x+2-(2-x) equation: 



2(x-3)+1=3x+2-(2-x)

We move all terms to the left:

2(x-3)+1-(3x+2-(2-x))=0

We add all the numbers together, and all the variables

2(x-3)-(3x+2-(-1x+2))+1=0

We multiply parentheses

2x-(3x+2-(-1x+2))-6+1=0



We calculate terms in parentheses: -(3x+2-(-1x+2)), so:

3x+2-(-1x+2)

determiningTheFunctionDomain
3x-(-1x+2)+2

We get rid of parentheses

3x+1x-2+2

We add all the numbers together, and all the variables

4x

Back to the equation:

-(4x)



We add all the numbers together, and all the variables

-2x-5=0

We move all terms containing x to the left, all other terms to the right

-2x=5

x=5/-2

x=-2+1/2

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