2(x-3)+1=5-4(x-2)

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Solution for 2(x-3)+1=5-4(x-2) equation: 



2(x-3)+1=5-4(x-2)

We move all terms to the left:

2(x-3)+1-(5-4(x-2))=0

We multiply parentheses

2x-(5-4(x-2))-6+1=0



We calculate terms in parentheses: -(5-4(x-2)), so:

5-4(x-2)

determiningTheFunctionDomain
-4(x-2)+5

We multiply parentheses

-4x+8+5

We add all the numbers together, and all the variables

-4x+13

Back to the equation:

-(-4x+13)



We add all the numbers together, and all the variables

2x-(-4x+13)-5=0

We get rid of parentheses

2x+4x-13-5=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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