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2(x-3)+20=2(x+2)+9
We move all terms to the left:
2(x-3)+20-(2(x+2)+9)=0
We multiply parentheses
2x-(2(x+2)+9)-6+20=0
We calculate terms in parentheses: -(2(x+2)+9), so:We add all the numbers together, and all the variables
2(x+2)+9
We multiply parentheses
2x+4+9
We add all the numbers together, and all the variables
2x+13
Back to the equation:
-(2x+13)
2x-(2x+13)+14=0
We get rid of parentheses
2x-2x-13+14=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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