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2(x-3)+2=2(2x-4)
We move all terms to the left:
2(x-3)+2-(2(2x-4))=0
We multiply parentheses
2x-(2(2x-4))-6+2=0
We calculate terms in parentheses: -(2(2x-4)), so:We add all the numbers together, and all the variables
2(2x-4)
We multiply parentheses
4x-8
Back to the equation:
-(4x-8)
2x-(4x-8)-4=0
We get rid of parentheses
2x-4x+8-4=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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