2(x-3)+2=4x-2(2+x)

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Solution for 2(x-3)+2=4x-2(2+x) equation: 



2(x-3)+2=4x-2(2+x)

We move all terms to the left:

2(x-3)+2-(4x-2(2+x))=0

We add all the numbers together, and all the variables

2(x-3)-(4x-2(x+2))+2=0

We multiply parentheses

2x-(4x-2(x+2))-6+2=0



We calculate terms in parentheses: -(4x-2(x+2)), so:

4x-2(x+2)

We multiply parentheses

4x-2x-4

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

2x-(2x-4)-4=0

We get rid of parentheses

2x-2x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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