2(x-3)+2x=3x+12

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Solution for 2(x-3)+2x=3x+12 equation: 



2(x-3)+2x=3x+12

We move all terms to the left:

2(x-3)+2x-(3x+12)=0

We add all the numbers together, and all the variables

2x+2(x-3)-(3x+12)=0

We multiply parentheses

2x+2x-(3x+12)-6=0

We get rid of parentheses

2x+2x-3x-12-6=0

We add all the numbers together, and all the variables

x-18=0

We move all terms containing x to the left, all other terms to the right

x=18

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