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2(x-3)+3(2x+1)=53
We move all terms to the left:
2(x-3)+3(2x+1)-(53)=0
We multiply parentheses
2x+6x-6+3-53=0
We add all the numbers together, and all the variables
8x-56=0
We move all terms containing x to the left, all other terms to the right
8x=56
x=56/8
x=7
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