2(x-3)+3(x+2)=18

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Solution for 2(x-3)+3(x+2)=18 equation: 



2(x-3)+3(x+2)=18

We move all terms to the left:

2(x-3)+3(x+2)-(18)=0

We multiply parentheses

2x+3x-6+6-18=0

We add all the numbers together, and all the variables

5x-18=0

We move all terms containing x to the left, all other terms to the right

5x=18

x=18/5

x=3+3/5

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