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2(x-3)+3(x-1)=5x+4(x-4)
We move all terms to the left:
2(x-3)+3(x-1)-(5x+4(x-4))=0
We multiply parentheses
2x+3x-(5x+4(x-4))-6-3=0
We calculate terms in parentheses: -(5x+4(x-4)), so:We add all the numbers together, and all the variables
5x+4(x-4)
We multiply parentheses
5x+4x-16
We add all the numbers together, and all the variables
9x-16
Back to the equation:
-(9x-16)
5x-(9x-16)-9=0
We get rid of parentheses
5x-9x+16-9=0
We add all the numbers together, and all the variables
-4x+7=0
We move all terms containing x to the left, all other terms to the right
-4x=-7
x=-7/-4
x=1+3/4
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