2(x-3)+3(x-4)+4(x-5)=0

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Solution for 2(x-3)+3(x-4)+4(x-5)=0 equation:


2(x-3)+3(x-4)+4(x-5)=0

We simplify the equation to the form, which is simple to understand
2(x-3)+3(x-4)+4(x-5)=0

Reorder the terms in parentheses
+(+2x-6)+3*(x-4)+4*(x-5)=0

Remove unnecessary parentheses
+2x-6+3+*(+x-4+)+4+*(+x-5+)=0

Reorder the terms in parentheses
+2x-6+(+3x-12)+4*(x-5)=0

Remove unnecessary parentheses
+2x-6+3x-12+4+*(+x-5+)=0

Reorder the terms in parentheses
+2x-6+3x-12+(+4x-20)=0

Remove unnecessary parentheses
+2x-6+3x-12+4x-20=0

We move all terms containing x to the left and all other terms to the right.
+2x+3x+4x=0+6+12+20

We simplify left and right side of the equation.
+9x=+38

We divide both sides of the equation by 9 to get x.
x=4.22222222222

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