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2(x-3)+3(x-4)=5(2x-3)+1
We move all terms to the left:
2(x-3)+3(x-4)-(5(2x-3)+1)=0
We multiply parentheses
2x+3x-(5(2x-3)+1)-6-12=0
We calculate terms in parentheses: -(5(2x-3)+1), so:We add all the numbers together, and all the variables
5(2x-3)+1
We multiply parentheses
10x-15+1
We add all the numbers together, and all the variables
10x-14
Back to the equation:
-(10x-14)
5x-(10x-14)-18=0
We get rid of parentheses
5x-10x+14-18=0
We add all the numbers together, and all the variables
-5x-4=0
We move all terms containing x to the left, all other terms to the right
-5x=4
x=4/-5
x=-4/5
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