2(x-3)+36=7(x-2)

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Solution for 2(x-3)+36=7(x-2) equation: 



2(x-3)+36=7(x-2)

We move all terms to the left:

2(x-3)+36-(7(x-2))=0

We multiply parentheses

2x-(7(x-2))-6+36=0



We calculate terms in parentheses: -(7(x-2)), so:

7(x-2)

We multiply parentheses

7x-14

Back to the equation:

-(7x-14)



We add all the numbers together, and all the variables

2x-(7x-14)+30=0

We get rid of parentheses

2x-7x+14+30=0

We add all the numbers together, and all the variables

-5x+44=0

We move all terms containing x to the left, all other terms to the right

-5x=-44

x=-44/-5

x=8+4/5

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