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2(x-3)+3x=2-2(3x-7)
We move all terms to the left:
2(x-3)+3x-(2-2(3x-7))=0
We add all the numbers together, and all the variables
3x+2(x-3)-(2-2(3x-7))=0
We multiply parentheses
3x+2x-(2-2(3x-7))-6=0
We calculate terms in parentheses: -(2-2(3x-7)), so:We add all the numbers together, and all the variables
2-2(3x-7)
determiningTheFunctionDomain -2(3x-7)+2
We multiply parentheses
-6x+14+2
We add all the numbers together, and all the variables
-6x+16
Back to the equation:
-(-6x+16)
5x-(-6x+16)-6=0
We get rid of parentheses
5x+6x-16-6=0
We add all the numbers together, and all the variables
11x-22=0
We move all terms containing x to the left, all other terms to the right
11x=22
x=22/11
x=2
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