2(x-3)+4(2x+1)=48

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Solution for 2(x-3)+4(2x+1)=48 equation: 



2(x-3)+4(2x+1)=48

We move all terms to the left:

2(x-3)+4(2x+1)-(48)=0

We multiply parentheses

2x+8x-6+4-48=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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