2(x-3)+4=7(x-2)+8x

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Solution for 2(x-3)+4=7(x-2)+8x equation: 



2(x-3)+4=7(x-2)+8x

We move all terms to the left:

2(x-3)+4-(7(x-2)+8x)=0

We multiply parentheses

2x-(7(x-2)+8x)-6+4=0



We calculate terms in parentheses: -(7(x-2)+8x), so:

7(x-2)+8x

We add all the numbers together, and all the variables

8x+7(x-2)

We multiply parentheses

8x+7x-14

We add all the numbers together, and all the variables

15x-14

Back to the equation:

-(15x-14)



We add all the numbers together, and all the variables

2x-(15x-14)-2=0

We get rid of parentheses

2x-15x+14-2=0

We add all the numbers together, and all the variables

-13x+12=0

We move all terms containing x to the left, all other terms to the right

-13x=-12

x=-12/-13

x=12/13

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