2(x-3)+4x+4=(4-x)5

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Solution for 2(x-3)+4x+4=(4-x)5 equation: 



2(x-3)+4x+4=(4-x)5

We move all terms to the left:

2(x-3)+4x+4-((4-x)5)=0

We add all the numbers together, and all the variables

2(x-3)+4x-((-1x+4)5)+4=0

We add all the numbers together, and all the variables

4x+2(x-3)-((-1x+4)5)+4=0

We multiply parentheses

4x+2x-((-1x+4)5)-6+4=0



We calculate terms in parentheses: -((-1x+4)5), so:

(-1x+4)5

We multiply parentheses

-5x+20

Back to the equation:

-(-5x+20)



We add all the numbers together, and all the variables

6x-(-5x+20)-2=0

We get rid of parentheses

6x+5x-20-2=0

We add all the numbers together, and all the variables

11x-22=0

We move all terms containing x to the left, all other terms to the right

11x=22

x=22/11

x=2

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