2(x-3)+4x-(x+1)=3x+5(2x-3)-2

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Solution for 2(x-3)+4x-(x+1)=3x+5(2x-3)-2 equation: 



2(x-3)+4x-(x+1)=3x+5(2x-3)-2

We move all terms to the left:

2(x-3)+4x-(x+1)-(3x+5(2x-3)-2)=0

We add all the numbers together, and all the variables

4x+2(x-3)-(x+1)-(3x+5(2x-3)-2)=0

We multiply parentheses

4x+2x-(x+1)-(3x+5(2x-3)-2)-6=0

We get rid of parentheses

4x+2x-x-(3x+5(2x-3)-2)-1-6=0



We calculate terms in parentheses: -(3x+5(2x-3)-2), so:

3x+5(2x-3)-2

We multiply parentheses

3x+10x-15-2

We add all the numbers together, and all the variables

13x-17

Back to the equation:

-(13x-17)



We add all the numbers together, and all the variables

5x-(13x-17)-7=0

We get rid of parentheses

5x-13x+17-7=0

We add all the numbers together, and all the variables

-8x+10=0

We move all terms containing x to the left, all other terms to the right

-8x=-10

x=-10/-8

x=1+1/4

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