2(x-3)+4x=-3(x-2)-4

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Solution for 2(x-3)+4x=-3(x-2)-4 equation: 



2(x-3)+4x=-3(x-2)-4

We move all terms to the left:

2(x-3)+4x-(-3(x-2)-4)=0

We add all the numbers together, and all the variables

4x+2(x-3)-(-3(x-2)-4)=0

We multiply parentheses

4x+2x-(-3(x-2)-4)-6=0



We calculate terms in parentheses: -(-3(x-2)-4), so:

-3(x-2)-4

We multiply parentheses

-3x+6-4

We add all the numbers together, and all the variables

-3x+2

Back to the equation:

-(-3x+2)



We add all the numbers together, and all the variables

6x-(-3x+2)-6=0

We get rid of parentheses

6x+3x-2-6=0

We add all the numbers together, and all the variables

9x-8=0

We move all terms containing x to the left, all other terms to the right

9x=8

x=8/9

x=8/9

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