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2(x-3)+4x=2(3x+1)
We move all terms to the left:
2(x-3)+4x-(2(3x+1))=0
We add all the numbers together, and all the variables
4x+2(x-3)-(2(3x+1))=0
We multiply parentheses
4x+2x-(2(3x+1))-6=0
We calculate terms in parentheses: -(2(3x+1)), so:We add all the numbers together, and all the variables
2(3x+1)
We multiply parentheses
6x+2
Back to the equation:
-(6x+2)
6x-(6x+2)-6=0
We get rid of parentheses
6x-6x-2-6=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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