2(x-3)+4x=7(x+2)-5x

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Solution for 2(x-3)+4x=7(x+2)-5x equation: 



2(x-3)+4x=7(x+2)-5x

We move all terms to the left:

2(x-3)+4x-(7(x+2)-5x)=0

We add all the numbers together, and all the variables

4x+2(x-3)-(7(x+2)-5x)=0

We multiply parentheses

4x+2x-(7(x+2)-5x)-6=0



We calculate terms in parentheses: -(7(x+2)-5x), so:

7(x+2)-5x

We add all the numbers together, and all the variables

-5x+7(x+2)

We multiply parentheses

-5x+7x+14

We add all the numbers together, and all the variables

2x+14

Back to the equation:

-(2x+14)



We add all the numbers together, and all the variables

6x-(2x+14)-6=0

We get rid of parentheses

6x-2x-14-6=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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