2(x-3)+5=3(x-2)+8

Solution for 2(x-3)+5=3(x-2)+8 equation:

2(x-3)+5=3(x-2)+8

We move all terms to the left:

2(x-3)+5-(3(x-2)+8)=0

We multiply parentheses

2x-(3(x-2)+8)-6+5=0


We calculate terms in parentheses: -(3(x-2)+8), so:

3(x-2)+8

We multiply parentheses

3x-6+8

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)


We add all the numbers together, and all the variables

2x-(3x+2)-1=0

We get rid of parentheses

2x-3x-2-1=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3