2(x-3)+5=9(b+2)+1

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Solution for 2(x-3)+5=9(b+2)+1 equation:


Simplifying
2(x + -3) + 5 = 9(b + 2) + 1

Reorder the terms:
2(-3 + x) + 5 = 9(b + 2) + 1
(-3 * 2 + x * 2) + 5 = 9(b + 2) + 1
(-6 + 2x) + 5 = 9(b + 2) + 1

Reorder the terms:
-6 + 5 + 2x = 9(b + 2) + 1

Combine like terms: -6 + 5 = -1
-1 + 2x = 9(b + 2) + 1

Reorder the terms:
-1 + 2x = 9(2 + b) + 1
-1 + 2x = (2 * 9 + b * 9) + 1
-1 + 2x = (18 + 9b) + 1

Reorder the terms:
-1 + 2x = 18 + 1 + 9b

Combine like terms: 18 + 1 = 19
-1 + 2x = 19 + 9b

Solving
-1 + 2x = 19 + 9b

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 2x = 19 + 1 + 9b

Combine like terms: -1 + 1 = 0
0 + 2x = 19 + 1 + 9b
2x = 19 + 1 + 9b

Combine like terms: 19 + 1 = 20
2x = 20 + 9b

Divide each side by '2'.
x = 10 + 4.5b

Simplifying
x = 10 + 4.5b

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