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2(x-3)+5x=5(2x+1)
We move all terms to the left:
2(x-3)+5x-(5(2x+1))=0
We add all the numbers together, and all the variables
5x+2(x-3)-(5(2x+1))=0
We multiply parentheses
5x+2x-(5(2x+1))-6=0
We calculate terms in parentheses: -(5(2x+1)), so:We add all the numbers together, and all the variables
5(2x+1)
We multiply parentheses
10x+5
Back to the equation:
-(10x+5)
7x-(10x+5)-6=0
We get rid of parentheses
7x-10x-5-6=0
We add all the numbers together, and all the variables
-3x-11=0
We move all terms containing x to the left, all other terms to the right
-3x=11
x=11/-3
x=-3+2/3
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