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2(x-3)+5x=8x+3(x+4)
We move all terms to the left:
2(x-3)+5x-(8x+3(x+4))=0
We add all the numbers together, and all the variables
5x+2(x-3)-(8x+3(x+4))=0
We multiply parentheses
5x+2x-(8x+3(x+4))-6=0
We calculate terms in parentheses: -(8x+3(x+4)), so:We add all the numbers together, and all the variables
8x+3(x+4)
We multiply parentheses
8x+3x+12
We add all the numbers together, and all the variables
11x+12
Back to the equation:
-(11x+12)
7x-(11x+12)-6=0
We get rid of parentheses
7x-11x-12-6=0
We add all the numbers together, and all the variables
-4x-18=0
We move all terms containing x to the left, all other terms to the right
-4x=18
x=18/-4
x=-4+1/2
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