2(x-3)+6=3(x-2)+5

Solution for 2(x-3)+6=3(x-2)+5 equation:

2(x-3)+6=3(x-2)+5

We move all terms to the left:

2(x-3)+6-(3(x-2)+5)=0

We multiply parentheses

2x-(3(x-2)+5)-6+6=0


We calculate terms in parentheses: -(3(x-2)+5), so:

3(x-2)+5

We multiply parentheses

3x-6+5

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)


We add all the numbers together, and all the variables

2x-(3x-1)=0

We get rid of parentheses

2x-3x+1=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1