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2(x-3)+6x=3(5+3x)
We move all terms to the left:
2(x-3)+6x-(3(5+3x))=0
We add all the numbers together, and all the variables
2(x-3)+6x-(3(3x+5))=0
We add all the numbers together, and all the variables
6x+2(x-3)-(3(3x+5))=0
We multiply parentheses
6x+2x-(3(3x+5))-6=0
We calculate terms in parentheses: -(3(3x+5)), so:We add all the numbers together, and all the variables
3(3x+5)
We multiply parentheses
9x+15
Back to the equation:
-(9x+15)
8x-(9x+15)-6=0
We get rid of parentheses
8x-9x-15-6=0
We add all the numbers together, and all the variables
-1x-21=0
We move all terms containing x to the left, all other terms to the right
-x=21
x=21/-1
x=-21
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