2(x-3)+7(x-2)+3=10

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Solution for 2(x-3)+7(x-2)+3=10 equation: 



2(x-3)+7(x-2)+3=10

We move all terms to the left:

2(x-3)+7(x-2)+3-(10)=0

We add all the numbers together, and all the variables

2(x-3)+7(x-2)-7=0

We multiply parentheses

2x+7x-6-14-7=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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