2(x-3)+7-4(x+1)=3

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Solution for 2(x-3)+7-4(x+1)=3 equation:


Simplifying
2(x + -3) + 7 + -4(x + 1) = 3

Reorder the terms:
2(-3 + x) + 7 + -4(x + 1) = 3
(-3 * 2 + x * 2) + 7 + -4(x + 1) = 3
(-6 + 2x) + 7 + -4(x + 1) = 3

Reorder the terms:
-6 + 2x + 7 + -4(1 + x) = 3
-6 + 2x + 7 + (1 * -4 + x * -4) = 3
-6 + 2x + 7 + (-4 + -4x) = 3

Reorder the terms:
-6 + 7 + -4 + 2x + -4x = 3

Combine like terms: -6 + 7 = 1
1 + -4 + 2x + -4x = 3

Combine like terms: 1 + -4 = -3
-3 + 2x + -4x = 3

Combine like terms: 2x + -4x = -2x
-3 + -2x = 3

Solving
-3 + -2x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -2x = 3 + 3

Combine like terms: -3 + 3 = 0
0 + -2x = 3 + 3
-2x = 3 + 3

Combine like terms: 3 + 3 = 6
-2x = 6

Divide each side by '-2'.
x = -3

Simplifying
x = -3

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