2(x-3)+7=10-3(x+5)

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Solution for 2(x-3)+7=10-3(x+5) equation: 



2(x-3)+7=10-3(x+5)

We move all terms to the left:

2(x-3)+7-(10-3(x+5))=0

We multiply parentheses

2x-(10-3(x+5))-6+7=0



We calculate terms in parentheses: -(10-3(x+5)), so:

10-3(x+5)

determiningTheFunctionDomain
-3(x+5)+10

We multiply parentheses

-3x-15+10

We add all the numbers together, and all the variables

-3x-5

Back to the equation:

-(-3x-5)



We add all the numbers together, and all the variables

2x-(-3x-5)+1=0

We get rid of parentheses

2x+3x+5+1=0

We add all the numbers together, and all the variables

5x+6=0

We move all terms containing x to the left, all other terms to the right

5x=-6

x=-6/5

x=-1+1/5

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