2(x-3)+7=3(3x-2)

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Solution for 2(x-3)+7=3(3x-2) equation: 



2(x-3)+7=3(3x-2)

We move all terms to the left:

2(x-3)+7-(3(3x-2))=0

We multiply parentheses

2x-(3(3x-2))-6+7=0



We calculate terms in parentheses: -(3(3x-2)), so:

3(3x-2)

We multiply parentheses

9x-6

Back to the equation:

-(9x-6)



We add all the numbers together, and all the variables

2x-(9x-6)+1=0

We get rid of parentheses

2x-9x+6+1=0

We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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