2(x-3)+7=3(x+1)

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Solution for 2(x-3)+7=3(x+1) equation: 



2(x-3)+7=3(x+1)

We move all terms to the left:

2(x-3)+7-(3(x+1))=0

We multiply parentheses

2x-(3(x+1))-6+7=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

2x-(3x+3)+1=0

We get rid of parentheses

2x-3x-3+1=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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