2(x-3)+7=4(x-2)-2

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Solution for 2(x-3)+7=4(x-2)-2 equation: 



2(x-3)+7=4(x-2)-2

We move all terms to the left:

2(x-3)+7-(4(x-2)-2)=0

We multiply parentheses

2x-(4(x-2)-2)-6+7=0



We calculate terms in parentheses: -(4(x-2)-2), so:

4(x-2)-2

We multiply parentheses

4x-8-2

We add all the numbers together, and all the variables

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

2x-(4x-10)+1=0

We get rid of parentheses

2x-4x+10+1=0

We add all the numbers together, and all the variables

-2x+11=0

We move all terms containing x to the left, all other terms to the right

-2x=-11

x=-11/-2

x=5+1/2

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