2(x-3)+8=4x-2(-1+x)

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Solution for 2(x-3)+8=4x-2(-1+x) equation: 



2(x-3)+8=4x-2(-1+x)

We move all terms to the left:

2(x-3)+8-(4x-2(-1+x))=0

We add all the numbers together, and all the variables

2(x-3)-(4x-2(x-1))+8=0

We multiply parentheses

2x-(4x-2(x-1))-6+8=0



We calculate terms in parentheses: -(4x-2(x-1)), so:

4x-2(x-1)

We multiply parentheses

4x-2x+2

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

2x-(2x+2)+2=0

We get rid of parentheses

2x-2x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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